Simplify 2x2(4x3 - 3x2 + 6x).

Mathematics

2 answers:

Reil [10]2 years ago

7 0

Its hard to show you the steps just gotta payin attention to your teacher
anyway i tried my best to show you the steps
tbh if you needed explanation you should more points

vaieri [72.5K]2 years ago

7 0

Answer:

The simplified form of the provided expression is $8x^{5} - 6x^{4} + 12x^{3}$

Step-by-step explanation:

Consider the provided expression.

$2x^2(4x^3 - 3x^2 + 6x)$

Use the distributive property:

$a(b+c)=ab+ac$

By using the above property we can simplify it as shown:

$2x^2(4x^3 - 3x^2 + 6x)$

$8x^{(2+3)} - 6x^{(2+2)} + 12x^{(2+1)}$

$8x^{5} - 6x^{4} + 12x^{3}$

Thus, the simplified form of the provided expression is $8x^{5} - 6x^{4} + 12x^{3}$

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Perform the indicated operation. Be sure the answer is reduced.<br><br> d+3/8d -2d+1/10d^2

mars1129 [50]

Answer:

$\frac{d(4d-25)}{40}$

Step-by-step explanation:

Given: $d+\frac{3}{8}d-2d+\frac{1}{10}d^2$

To find: the value of given expression in reduced form

Solution:

$d+\frac{3}{8}d-2d+\frac{1}{10}d^2=\frac{d}{1}+\frac{3}{8}d-\frac{2d}{1}+\frac{1}{10}d^2$

Here, $L.C.M(1,8,1,10)=40$

( L.C.M of two or more numbers is the smallest positive number that is their multiple )

So,

$d+\frac{3}{8}d-2d+\frac{1}{10}d^2=\frac{d}{1}+\frac{3}{8}d-\frac{2d}{1}+\frac{1}{10}d^2\\=\frac{40d+15d-80d+4d^2}{40}\\=\frac{\left ( 40d+15d-80d \right )+4d^2}{40}\\=\frac{\left ( -25d \right )+4d^2}{40}\\=\frac{4d^2-25d}{40}\\=\frac{d(4d-25)}{40}$