For this question, we apply the Raoult's Law. The formula is written below:

P = P*x
where
P is the partial pressure
P* is the vapor pressure of the pure solvent
x is the mole fraction

The partial pressure is solved as follows:
P = Total P*x = (250 torr)(0.857) = 214.25 torr
Hence,
214.25 = (361 torr)(x)
<em>x = 0.593 or 59.3%</em>

8 0

3 years ago

How many grams of NH4Cl (ammonium chloride) should dissolve in 50mL of water at 20 degrees Celsius?

Anna71 [15]

Answer:

about 19 or 20 g

Explanation:

To do this, is neccesary to watch a solubility curve of this compound. This is the only way that you can know how many grams are neccesary to dissolve this compound in 50 mL of water to a given temperature.

Now, if you watched the attached graph, you can see the solubility curve of many compounds in 100 g of water (or 100 mL of water). So, to know how many do you need in 50 mL, it's just the half.

So watching the curve, you can see that at 20 °C, we simply need between 35 g and 40 g. Let's just say we need 38 grams of NH4Cl to be dissolved in 100 mL of water.

So, in 50 mL, it's just the half. So, we only need 19 g or 20 g of NH4Cl at 20 °C, to dissolve this compound in water.

3 0

2 years ago