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2 years ago

Item 14

Mathematics

1 answer:

andreyandreev [35.5K]2 years ago

8 0

Your collection's mean answers

median - 1930

range - 54

interquartile range - 50

mean absolute devitation - 23.75

Your friends collection mean answers

median - 1929.5

range - 15

interquartile range - 7

mean absolute devitation - 3.5

Would really appreciate a brainliest!!

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Vanessa throws a tennis ball in the air. the function h(t) = -16t2 + 45t + 7 represents the distance, in feet, that the ball is

antiseptic1488 [7]

Given that height, h(t) of a tennis ball is modeled by the equation h(t)=-16t^2 + 45t + 7, the time taken for the ball to reach maximum height will found as follows:
at maximum height:
h'(t)=0
but from the equation:
h'(t)=-32t+45=0
solving for t we get
t=45/32
t=1.40625~1.4 seconds
Thus the time taken to reach maximum height is 1.4 seconds

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2 years ago

Solve for the value of n (9n) (8n+8)

Hatshy [7]

Answer:

undoable

Step-by-step explanation:

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2 years ago

The modulus of (3 + 4i)4 is _____. 5 20 125 625

vladimir1956 [14]

(3+4i)*4 = 3*4+4i*4 = 12+16i

The complex number 12+16i is in the form a+bi where a = 12 and b = 16

m = modulus
m = distance from (0,0) to (a,b)
m = sqrt(a^2+b^2)
m = sqrt(12^2+16^2)
m = sqrt(144+256)
m = sqrt(400)
m = 20

Answer: 20

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2 years ago

Here are two closed containers and four balls just fit into each container. Each ball has a diameter of 60mm. Which container ha

Studentka2010 [4]

Answer:

Container B has smaller surface area.

Step-by-step explanation:

Given:

Container A

Radius = 60/2 = 30 mm

Height = 4 x 60 = 240 mm

Container B

Length = 120

Width = 120

Height = 60

Computation:

Surface area of container A (Cylinder) = 2πr[h+r]

Surface area of container A (Cylinder) = 2[22/7][60][120+60]

Surface area of container A (Cylinder) = 67,885.70 mm² (Approx)

Surface area of container B (Cuboid) = 2[lb+bh+hl]

Surface area of container B (Cuboid) = 2[(14,400)+(7,200)+(7,200)]

Surface area of container B (Cuboid) = 57,600 mm²

Container B has smaller surface area.

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2 years ago

What is the improper fraction for 5 1/3

Yakvenalex [24]

Hey there Shawn!

$\left[\begin{array}{ccc}\boxed{\boxed{ 5\frac{1}{3}= \frac{16}{3} }} \ as \ an \ improper \ fraction\end{array}\right]$

Hope this helps you budd!

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2 years ago