Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
?????????????????????/ us a calculator to add up all the nub.
Answer:
2156/9
Explanation:
The question states all the necessary values that we need for the ratio. The company created 2156 board games and 9 card games.
However, what we need to pay attention to here is the order of the ratio.
Because the question is “What is the ratio of the number of board games to the number of card games”, we know that we need to write the ratio so the number of board games is first.
Additionally, ratios can also be written like fractions. The first number of the ratio would be the top number/numerator in fraction form.
Therefore, the ratio of the number of board games to the number of card games is 2156:9
I hope this helps!
Answer: -2
=====================================================
Draw a vertical line through 4 on the x axis. This vertical line crosses the parabola at some point (which we'll call point A). Draw a horizontal line from point A to the y axis and note how it lands on y = 12. Therefore the point (4,12) is on this parabola.
Repeat the same steps as before to find that (8,4) is also on the parabola
We need to find the slope of the line through (4,12) and (8,4)
m = (y2 - y1)/(x2 - x1)
m = (4-12)/(8 - 4)
m = -8/4
m = -2
The slope of this line is -2 meaning that the average rate of change from x = 4 to x = 8 is -2.
The line goes down 2 units each time you move to the right 1 unit.
The appropriate response is a weighted average. It is a mean ascertained by giving qualities in an informational index more impact as indicated by some characteristic of the information. It is normal in which every amount to have arrived at the midpoint of is allocated a weight, and these weightings decide the relative significance of every amount on the normal.
