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2 years ago

In a parallel circuit the current A stays in one path B splits and goes through two components C makes one circle

Physics

1 answer:

ArbitrLikvidat [17]2 years ago

8 0

Answer:

B splits and goes through two components

Explanation:

- A series circuit is a circuit in which the components are all connected along the same branch: as a result, the current flowing through the components is the same, while the sum of the potential differences across each component is equal to the emf of the battery

- A parallel circuit is a circuit consisting of separate branches, so that each branch has a potential difference equal to the emf of the battery. As a result, in such a circuit the current in the circuit splits and goes through the different branches/components.

So, the correct answer is

B splits and goes through two components

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How does the water cycle affect weather and climate?

Drupady [299]

The water cycle has to do with precipitation, evaporation, condensation, transpiration, runoff, and many other processes which is the form of weather like storms, tornadoes, hurricanes, etc. There's many different kinds of precipitation and every one is different and that will affect the climate. Moisture and condensation will also affect the climate and the weather.

Hope this helps you!

6 0

3 years ago

Read 2 more answers

A truck driver is broadcasting at a frequency of 27.075 MHz with a CB (citizen's band) radio. Determine the wavelength of the el

Sergio [31]

Answer:

11m

Explanation:

Wavelength of a wave is the distance between successive crests and trough of a wave. It is represented mathematically as the ratio of the speed of the wave to its frequency. It can be expressed as;

Wavelength ¶ = wave speed (v) /frequency (f)

Given the speed of light c = 2.9979 10^8 m/s.

frequency of the radio wave = 27.075 MHz = 27.075×10^6Hz

Wavelength = 2.9979 10^8/27.075×10^6

Wavelength = 0.11×10^2

Wavelength = 11m

Therefore, the wavelength of the electromagnetic wave being used is 11m

3 0

2 years ago

An electron is moving in the presence of an electric field of 400 N/C. What force does the electron experience?

yanalaym [24]

Answer:

Explanation:

Given

Electric Field strength $E=400\ N/C$

charge of electron $q=1.6\times 10^{-19}\ C$

Force on the charge particle is given by

$F=qE$

$F=1.6\times 10^{-19}\times 400$

$F=640\times 10^{-19}\ N$

but this force will be acting in the direction opposite to the direction of Electric field because electron is negatively charged

8 0

2 years ago

A capacitor is charged until it holds 5.0 j of energy. it is then connected across a 10-kω resistor. in 13.6 ms , the resistor d

prohojiy [21]

Answer:

The capacite is C=5.32 uF using the equations of voltage and energy in capacitance

Explanation:

The energy holds is 5 J and the resistor dissipates 2J so the energy total is 3J

Using:

$V_{t}= V_{o}e^{\frac{-t}{R*C} }$

Voltage in this case is the energy dissipated so

$E_{t}= E_{o}e^{\frac{-t}{R*C} }$

$\frac{\sqrt{E_t} }{\sqrt{E_o} } = e^{\frac{-t}{R*C} }$

$\frac{\sqrt{3 J} }{\sqrt{5J} } = e^{\frac{-13.6ms}{10kw*C} }$

Using the equation to find capacitance

$ln 0.775= e^{\frac{-13.6 x10^{3} }{10x10^{3}*C }} \\ln(0.775)= ln * e^{\frac{-13.6 x10^{3s} }{10x10^{3}*C }} \\\\ln(0.775)= {\frac{-13.6 x10^{3} }{10x10^{3}*C }} \\C= \frac{-13.6 x10^{-3} }{10x10x^{3}*ln(0.775) }$