F-1(x) = (x-7) / 2, you can get this by taking 2x + 7, and doing the opposite operations on x. you also need to go in the reverse direction of Order of Operations. So first, we take 7 away from x, since subtraction is opposite from addition, and it is the last thing we would do in order of operations. next we only have the 2 multiplier left, so we put the x-7 in parenthesis, and divide by 2.
Trick question it grew exactly 2 cm since we don't know the value of d there can't be an outcome
1. Regroup terms
x(x+5)=104
2. Expand
x^2+5x=104
3. Move all terms to one side
x^2+5x-104=0
4. Factor x^2+5x-104
(x-8)(x+13)=0
5. Solve for x
x=8 or x=-13
Since x<0 is not possible in this case, x=8
6. Finding the dimensions
We know that one side has to be x+5, and now that we know x:
8+5=13
13*8=104
The dimensions are 13 and 8, have a nice day :D
If you calculate 240/48, you will get 5 without any remainder, which means if you get 5 buses it can exactly take all students?
I'm only going to alter the left hand side. The right side will stay the same the entire time
I'll use the identity tan(x) = sin(x)/cos(x) and cot(x) = cos(x)/sin(x)
I'll also use sin(x+y) = sin(x)cos(y)+cos(x)sin(y) and cos(x+y) = cos(x)cos(y)-sin(x)sin(y)
So with that in mind, this is how the steps would look:
tan(x+pi/2) = -cot x
sin(x+pi/2)/cos(x+pi/2) = -cot x
(sin(x)cos(pi/2)+cos(x)sin(pi/2))/(cos(x)cos(pi/2)-sin(x)sin(pi/2)) = -cot x
(sin(x)*0+cos(x)*1)/(cos(x)*0-sin(x)*1) = -cot x
(0+cos(x))/(-sin(x)-0) = -cot x
(cos(x))/(-sin(x)) = -cot x
-cot x = -cot x
Identity is confirmed