Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Answer:
<em> </em><em>1</em><em>:</em><em>4</em>
<em>hope</em><em> </em><em>helpful</em><em> </em>:) !!!!
Answer:
Step-by-step explanation:
Magnitude: |a|= 
Direction: in the negative direction of the Ox axe and Oy axe
Answer:
(0, 9 ) and (- 4, 1 )
Step-by-step explanation:
To determine which ordered pairs lie on the graph substitute the x- coordinate of the point into the right side of the equation and compare the value obtained with the y- coordinate
(- 20, - 49 )
2x + 9 = (2 × - 20) + 9 = - 40 + 9 = - 31 ≠ - 49
(1, 10 )
2x + 9 = (2 × 1) + 9 = 2 + 9 = 11 ≠ 10
(0, 9 )
2x + 9 = (2 × 0) + 9 = 0 + 9 = 9 ← point lies on graph
(- 4, 1 )
2x + 9 = (2 × - 4) + 9 = - 8 + 9 = 1 ← point lies on graph
(- 3, 40 )
2x + 9 = ( 2 × - 3) + 9 = - 6 + 9 = 3 ≠ 40
