We know that the heights and bases of all of the parallelograms will be the same because they are equal, therefore, since the height of 2 parallelograms is 14, the height of one parallelogram is 14 / 2 = 7. Since the areas of all of the parallelograms are congruent, the area of one parallelogram is 308 / 4 = 77. The parallelogram area formula is A = bh where A, b and h are area, base and height respectively and we know both the area and height so we need to solve for b. Doing so we get 77 = b * 7 so that means b = 11. The length of y is two bases + 6 and since we know the base is 11, y = 11 * 2 + 6 = 22 + 6 = 28.
<span> The answer is is 4 times. </span> <span>The reason it is 4 is because 3 times 4 is 12 and 12 is less than 14. If you did 3 quarters times 5, you would get 15, going over the limit.</span>