Y = -1/5x + 3 ; (2,8)

The next event requires each runner to jump 8 hurdles that are spaced 12.3 meters apart. If there are 15 meters from the startin

inessss [21]

The race is 111.6 m long.

8 hurdles spaced 12.3 m apart means 7 spaces that are 12.3 m in length; 7*12.3 = 86.1

Add to this the distance to the first hurdle and the distance from the last hurdle:
86.1+15+10.5 = 111.6 m

3 0

2 years ago

Which statement correctly describes the graph of y = x + 9.5?

Vikki [24]

Answer:

A is the answer

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve the absolute value equation. If no solution write NO SOLUTION. -{2x + 3] + 8 12

Natasha2012 [34]

Answer:

If problem is "-|2x+3|+8=12"

then there is (no solution.)

Step-by-step explanation:

Let's solve your equation step-by-step.

−|2x+3|+8=12

Step 1: Add -8 to both sides.

−|2x+3|+8+−8=12+−8

−|2x+3|=4

Step 2: Divide both sides by -1.

−|2x+3|=4

-1 -1

|2x+3|=−4

Step 3: Solve Absolute Value.

|2x+3|=−4

No solutions Because absolute value is less than 0.

4 0

2 years ago

Vhich of the following is a true statement about skew lines?

krok68 [10]

Answer:

A. Skew lines cannot lie in the same plane.

Step-by-step explanation:

(*Which)

Skew Line Definition (from Wikipedia): "In three-dimensional geometry, skew lines are two lines that do not intersect and are not parallel." -Wikipedia

"Two lines that both lie in the same plane must either cross each other or be parallel, so skew lines can exist only in three or more dimensions." -Wikipedia

Skew lines cannot lie in the same plane so A is correct and C is incorrect.

B and D are incorrect because our friend Wikipedia just said it was incorrect.

5 0

2 years ago

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

2 years ago