All categories

2 years ago

Can u Please Help Me (20 Points)

Mathematics

1 answer:

sergeinik [125]2 years ago

5 0

897+450+328= 1675

(Not sure if this is a joke?)

You might be interested in

Suppose sarah is trying to design a metal box (a rectangular prism), which will hold 450 cubic centimeters of liquid. the length

schepotkina [342]

<span>So, the volume of a container can also be thought of as the amount of liquid that the container is capable of holding. It follows that 450=(length)(width)(height). The constraints of the problem say that the length of the box must be twice as large as the width, so it follows that j(height)=(2w)(w)(height)-450. This then implies that j(height)=(2w^2)(height)-450. In simpler terms, the height is defined as 450/(2w^2), or j(w)=450/(2w^2).</span>

5 0

2 years ago

If $1000 is divided equally amung 12 people about how much will each person reserve?

Dmitry_Shevchenko [17]

$1,000/12 = 83.3 repeated
Each person will reserve about $83.

3 0

2 years ago

Read 2 more answers

HELP ME PLZ!!!!! Plz!!!

Charra [1.4K]

Answer:

hi the right answer is option C.112

here's why:

$\frac{14}{50} \times 400 = 112$

4 0

2 years ago

Janet, an experienced shipping clerk, can fill a certain order in 7 hours. Jim, a new clerk, needs 9 hours to do the same job.

fiasKO [112]

Answer:

zhdhsgscsisgege8djdhshsyw7273yeh3737eyd

3 0

2 years ago

When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

3 0

2 years ago