If a quadrilateral has exactly 2 lines of symmetry and both are angle bisectors then which statement would be true
2 answers:
If a quadrilateral has exactly 2 lines of symmetry and both are angle bisectors then the figure must be a rhombus because it has exactly 2 pairs of congruent angles. I hope this helps! :)
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If 1/4 of x is 16, we multiply 16 x 4 which will give us x=64. 3/4 of 64 = 48
Step-by-step explanation:
5x-7+3x+27=180
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8x=160
x=20°.
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I think its c
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