Answer:
maximum height is 4.058 metres
Time in air = 0.033 second
Step-by-step explanation:
Given that the equation height h
h = -212t^2 + 7t + 4
What is the toy's maximum height?
Let us assume that the equation is a perfect parabola
Time t at Maximum height will be
t = -b/2a
Where b = 7 and a = - 212
t = -7/ - 212 ×2
t = 7/ 424 = 0.0165s
Substitute t in the main equation
h = - 212(7/424)^2 + 7(7/424) + 4
h = - 0.05778 + 0.115567 + 4
h = 4.058 metres
Therefore the maximum height is 4.058 metres
How long is the toy in the air?
The object will go up and return to the ground.
At ground level, h = 0
-212t^2 + 7t + 4 = 0
212t^2 - 7t - 4 = 0
You can factorize the above equation and pick the positive time t since time can't be negative
Or
Since we have assumed that it's a perfect parabola,
Total time in air = (-b/2a) × 2
Time in air = 0.0165 × 2 = 0.033 s
Answer:
Step-by-step explanation:
-4<n≤5
I would use the equation
24 + 8x = 112
let x = the amount of CDs she bought.
Hope this helps!!
Answer:
24.3 units (3 s.f.)
Step-by-step explanation:
Since a square has 4 equal sides,
perimeter of ABCD= 4(length of AB)
Distance between 2 points
=
Length of AB
perimeter of ABCD
all the coordinates of the original triangle have been multiplied by 1/2
A (-4,-6) x 1/2 = -2,-3
B (-8,2) * 1/2 = -4,1
C (-2,4) *1/2 = -1,2
so the scale factor is 1/2
Answer is B