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2 years ago

A man has a mass of 110kg. What is his weight?

Physics

1 answer:

Stells [14]2 years ago

5 0

His weight depends on where he is, because

Weight = (mass) x (gravity in the place where the mass is) .

For example:

-- If this man is on Mars, his weight is (110 kg) x (3.7 m/s²) = 408 Newtons

-- If he is on the Moon, his weight is (110 kg) x (1.6 m/s²) = 176 Newtons

-- If he is on Earth, his weight is (110 kg) x (9.8 m/s²) = 1,078 Newtons

-- If he is in a spacecraft coasting from one to another, his weight is zero.

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To drive a car at a constant velocity, you

kipiarov [429]

Answer:

the answer is C

Explanation:

The car, first is at rest and if you don't accelerate it won't move. When to hit the gas it will accelerate from rest

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1 year ago

Consider a system to be two train cars traveling toward each other. What is the total momentum of the system before the train ca

Brut [27]

Let say the two train cars are of masses $m_1$ and $m_2$

now if the speed of two cars are $v_1$ and $v_2$

then we can say that the momentum of two cars before they collide is given by

$P = m_1v_1 - m_2v_2$

here two cars are moving in opposite direction so we can say that the net momentum is subtraction of two cars momentum.

Now since in these two car motion there is no external force on them while they collide

So the momentum of two cars are always conserved.

hence we can say that the final momentum of two cars will be same after collision as it is before collision

$P = m_1v_1 - m_2v_2$

5 0

2 years ago

Read 2 more answers

Why might the 1990 earthquake and volcanic eruption in Luzon be related?

Art [367]

I am not sure but i think the answer is C

6 0

2 years ago

Can someone solve this problem and explain to me how you got it

evablogger [386]

Answer:

question5: F=74312.5N

question6: charge at the end of antenna=0.37N

Explanation:

Coulomb's law: the magnitude of the force of attraction or repulsion due to two charges is proportional to the product of the magnitude of the charges and inversely proportional to the square of distance between the charges.

⇒ $F\alpha\frac{q1*q2}{r^{2}}$

∴ $F=k\frac{q1*q2}{r^{2}}$

where $F$ is the force of attraction or repulsion

$k$ is Coulumb's constant= $9*10^{9}Nm^{2}C^{-2}$

$q1$ and $q2$ are the magnitude of the charges

$r$ is the distance between two charges

The force between the two charges is attractive if they are of different polarity

The force between the two charges is repulsive if they are of same polarity

Question5:

Given: q1=0.041 C, q2=0.029 C, r=12 m

therefore by Coulumb's law,

$F=9*10^{9}*\frac{0.041*0.029}{12^{2}}$

$F=74312.5N$

Question6:

Given: q1= $3*10^{-18}C$ , r=5 m, F= $4*10^{-11}N$

therefore by Coulumb's law,

$4*10^{-11}=9*10^{9}*\frac{3*10^{-18}*q2}{5^{2}}$

⇒ $q2=\frac{4*10^{-11}*25}{9*10^{9}*3*10^{-18}} \\=0.37C$

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2 years ago

What is the mathematical relationship between wavelength and energy transmission?.

Tomtit [17]

Answer: Wavelength is related to light and also related to energy. The shorter the wavelengths and the higher the frequency corresponds with greater energy. So the longer the wavelengths and lower the frequency results in lower energy. The energy equation is E = hν.

6 0

1 year ago