Answer:
- first mechanic: $105/hour
- second mechanic: $55/hour
Step-by-step explanation:
Let r represent the rate charged by the first mechanic. Then 160-r is the rate charged by the second mechanic. The total of charges is ...
20r +5(160-r) = 2375
15r +800 = 2375 . . . . . . eliminate parentheses
15r = 1575 . . . . . . . . . . . . subtract 800
r = 105 . . . . . . . . . . . . . . . divide by 15. First mechanic's rate.
160-r = 55 . . . . . Second mechanic's rate
The first mechanic charged $105 per hour; the second, $55 per hour.
For this case, the area is given by:
A = x * (200-2x)
Rewriting:
A = 200x-2x ^ 2
Deriving the expression we have:
A '= 200-4x
Equaling zero we have:
200-4x = 0
We clear x:
4x = 200
x = 200/4
x = 50 feet
Then, the maximum area is:
A (50) = 50 * (200-2 * 50)
A (50) = 5000 feet ^ 2
Answer:
the maximum possible area that can be enclosed with his 200ft of fencing is:
A (50) = 5000 feet ^ 2
1 recipe = 2/3 cup of butter.
3/4 recipe = 3/4 x 2/3 = 1/2 cup of butter
Answer: 1/2 cup of butter
Answer:
A. (x-5)(x-5)
Step-by-step explanation:
We need to factor x^2-10x+25 into the form (x+y)(x+y) where 2y=-10 and y^2=25
2y=-10
y=-5
So this becomes (x-5)(x-5)
Hope this helped!
Your answer would be y= 6x + 19
You get rid of the variable on the left side by adding it to both sides giving you y = 6x + 19
Hope it helps