Where must the fulcrum be located if a 300-pound weight and a 450-pound
1 answer:
Answer:
9 foot.
Step-by-step explanation:
From the question given, we were told that a 300-pound weight and a 450-pound weight are placed on each end of a 15-foot bar.
The diagram illustrating the question can be seen on the attached photo.
Weight 1 (W1) = 300 pound
Weight 2 (W2) = 450 pound.
Distance to which the fulcrum must be placed in order to balance (d1) = x
Distance from the other side of the bar (d2) = 15 – x
W1d1 = W2d2
300 × x = 450 (15 – x)
Clear bracket
300x = 6750 – 450x
Collect like terms
300x + 450x = 6750
750x = 6750
Divide both side by the coefficient of x i.e 750
x = 6750/750
x = 9 foot.
Therefore, the fulcrum must be placed at 9 foot in order to balance the bar.
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It has not been indicated whether the figure in the questions is a triangle or a quadrilateral. Irrespective of the shape, this can be solved. The two possible shapes and angles have been indicated in the attached image.
Now, from the information given we can infer that there is a line BD that cuts angle ABC in two parts: angle ABD and angle DBC
⇒ Angle ABC = Angle ABD + Angle DBC
Also, we know that angle ABC is 1 degree less than 3 times the angle ABD, and that angle DBC is 47 degree
Let angle ABD be x
⇒ Angle ABC = 3x-1
Also, Angle ABC = Angle ABD + Angle DBC
Substituting the values in the above equations
⇒ 3x-1 = x+47
⇒ 2x = 48
⇒ x = 24
So angle ABD = 24 degree, and angle ABC = 3(24)-1 = 71-1 = 71 degree
