Let A be the event 'made by Apex and defective':
P(A) = 0.67 x 0.11 = 0.0737
Let B be the event 'made by B-ink and defective':
P(B) = 0.33 x 0.06 = 0.0198
Let C be the event 'made by Apex or B-ink and defective':
P(C) = P(A) + P(B) = 0.0737 + 0.0198 = 0.0935
P(defective and made by Apex) = 0.0737/0.0935 = 0.788
The answer is 0.788 or 78.8%.
Answer:
Yes
Step-by-step explanation:
Given that in the June 2007 issue, Consumer Reports also examined the relative merits of top-loading and front-loading washing machines, testing samples of several different brands of each type.
The difference in mean values test gave a p value of 0.32
Confidence level = 95%
Alpha = 1-0.95 = 0.05
Compare p with alpha, here p >alpha
Hence we accept null hypothesis that there is no difference in the means.
Confidence interval method also will yield the same result. i.e. confidence interval for difference of means would definitely contain 0 at 95% conf level.
So answer is yes
Eight more than the product of two and a number x
8+2x <== in mathematical form
Eight more= 8+
Product= multiply
number=x
~'Manda
Answer:
Step-by-step explanation:
Since the results for the standardized test are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = test reults
µ = mean score
σ = standard deviation
From the information given,
µ = 1700 points
σ = 75 points
We want to the probability that a student will score more than 1700 points. This is expressed as
P(x > 1700) = 1 - P(x ≤ 1700)
For x = 1700,
z = (1700 - 1700)/75 = 0/75 = 0
Looking at the normal distribution table, the probability corresponding to the z score is 0.5
P(x > 1700) = 1 - 0.5 = 0.5
