First find the length of leg BC by using the Pythagorean theorem BC=132+52=12 ft if we find the midpoint of BC which is 6 ft we find where the angle bisector would touch the BC. From there we construct another triangle ANC where AC is equal to 5 ft and NC is equal to 6 ft where we can again use the Pythagorean theorem to find the length of the hypotenuse which is the angle bisector AN=Angle Bisector=62+52<span>=7.8102 ft.</span>
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Given:
Point( 7, 5)
x = 7 and y=5
slope(m) = 1
We need to first find the intercept.
Substitute x=7, y=5 and m=1 into y=mx + b and solve for intercept(b)
5 = 1(7) + b
5 = 7 + b
5 - 7 = b
-2 = b
Now, form the equation by substituting the value of the slope and intercept into y=mx + b
y = x - 2
Answer:
x=1
Step-by-step explanation:
-34x+6=-28
-6 -6
-34x=-34
-34 -34
x=1
Subtract 6 from both sides. on the left the 6 will be canceled out and on the right -28-6= -34
Than you divide -34 on both sides on the left the -34 will be canceled and on the right -34 divided bt-34 is positive 1. So x equals 1.
Well to find this answer, I assume that you want me to help with finding the area. Let's start with the area of the stage. Off of the info you gave me, I assume that the stage and pit are rectangles. So to find the area of the rectangles, we need to use the area formula A=l×w. Plug in the numbers into the formula and we get A=10×5. So the area of the stage is 50 yards. Now do the same thing for the pit, and we get A=4×2. So the pit's area is 8 yards. Add 50 and 8 to get the total area and we get 58. So the stage and the orchestra pit take up 58 yards of floor space. Hope I helped!
Answer:
C=2
Step-by-step explanation:
(26/3 so remainder =2) place of C in alphabet = 3
