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2 years ago

Friction heats up the brake pads of a car as it stops what is this an example of?

Physics

1 answer:

Gnesinka [82]2 years ago

3 0

This an example of the law of Conservation of Energy.

The car has quite a bit of kinetic energy while it's rolling. If you want to stop it, you have to take that kinetic energy away from the car, AND you have to do something with that energy.

If it's an electric car or hybrid, you can turn the kinetic energy into electrical energy, put it back into the batteries, and use it again later.

If it's just an ordinary gas guzzler, there's no way to save the kinetic energy. You use the car's kinetic energy to scrape two rough surfaces together, that turns it into heat, and the air blows the heat away.

Next time you want the car to roll again, you have to make more, new, kinetic energy. So you take chemical energy out of more gas, and you use the motor to turn the chemical energy into kinetic energy.

It's all the law of Conservation of Energy ... in action.

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THE CORRECT CHOICE IS B

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2 years ago

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The octet rule states that in chemical compounds atoms tend to have

Marrrta [24]

Answer:

In chemical compounds, atoms tends to have the electron configuration of a noble gas.

Explanation:

The noble gases are unreactive because of their electron configurations. This noble gas neon has the electron configuration of 1s22s22p6 . It has a full outer shell and cannot incorporate any more electrons into the valence shell.

The octet rule states that atoms tend to form compounds in ways that give them eight valence electrons and thus the electron configuration of a noble gas. An exception to an octet of electrons is in the case of the first noble gas, helium, which only has two valence electrons.

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2 years ago

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Two cars are traveling along a straight road. Car A maintains a constant speed of 95 km/h and car B maintains a constant speed o

natulia [17]

Answer

given,

Speed of car A = 95 Km/h

= 95 x 0.278 = 26.41 m/s

Speed of Car B = 121 Km/h

= 121 x 0.278 = 33.64 m/s

Distance between Car A and B at t=0 = 41 Km

a) Distance travel by car B

d = 26.41 t + 41000

speed of the car A = 33.64 m/s

distance = s x t

26.41 t + 41000 = 33.64 x t

7.23 t = 41000

t = 5670.82 s

time taken by Car B to cross Car A is equal to t = 5670.82 s

distance traveled by car A

D = s x t = 26.41 x 5670.82 = 149766.25 m = 149.76 Km

b) distance travel by the car B in 30 s after overtaking car A

D' = s x t = 33.64 x 30 = 1009.2 m = 1 Km

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2 years ago

10 PTS. If an electromagnetic wave has a frequency of 8 ⋅ 10^14 H z , what is its wavelength? Use λ=V/F. The speed of light is 3

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Answer :

The wavelength would be 410 m/s

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2 years ago

James and John dive from an overhang into the lake below. James simply drops straight down from the edge. John takes a running s

liraira [26]

Answer:

Both of them reach the lake at the same time.

Explanation:

We have equation of motion s = ut + 0.5at²

Vertical motion of James : -

Initial velocity, u = 0 m/s

Acceleration, a = g

Displacement, s = h

Substituting,

s = ut + 0.5 at²

h = 0 x t + 0.5 x g x t²

$t_{James}=\sqrt{\frac{2h}{g}}$

Vertical motion of John : -

Initial velocity, u = 0 m/s

Acceleration, a = g

Displacement, s = h

Substituting,

s = ut + 0.5 at²

h = 0 x t + 0.5 x g x t²

$t_{John}=\sqrt{\frac{2h}{g}}$

So both times are same.

Both of them reach the lake at the same time.

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2 years ago