Tan x /(1 +sec x) + (1+sec x) /tan x
Tan x=sin x / cos x
1+ sec x=1 +1/cos x=(cos x+1)/cos x
Therefore:
tan x /(1 +sec x) =(sin x/cos x)/(cos x+1)/cos x=
=(sin x * cos x) / [cos x* (cos x+1)]=sin x /(Cos x+1)
(1+sec x) /tan x=[(cos x+1)/cos x] / (sin x/cos x)=
=[cos x(cos x+1)]/(sin x *cos x)=(cos x+1)/sin x
tan x /(1 +sec x) + (1+sec x) /tan x=
=sin x /(Cos x+1) + (cos x+1)/sin x=
=(sin²x+cos²x+2 cos x+1) / [sin x(cos x+1)]=
Remember: sin²x+cos²x=1⇒ sin²x=1-cos²x
=(1-cos²x+cos²x+2 cos x+1) / [sin x(cos x+1)]=
=2 cos x+2 / [sin x(cos x+1)]=
=2(cos x+1) / [sin x(cos x+1)]=
=2 /sin x
Answer : tan x /(1 +sec x) + (1+sec x) /tan x= 2/sin x
Both are getting bigger or increasing you need to rephrase the question
Answer:
-5/2+-2
Step-by-step explanation:
Answer:
Step-by-step explanation:
Step 1: Expand by distributing sum groups.
Step 2: Expand by distributing terms.
Step 3: Expand by distributing terms.
Step 4: Collect like terms.
Step 5: Simplify.
Answer: so your sister sends 14 messages a day
Step-by-step explanation: you send about twelve texts a day and as a total you both send 26 so lets let your sister be x and you are 12
26- 12=x
26-12= 14
I hope this was helpful!
