a= 6-2b-3c
then put that equation inside the first one and then the second one
you get -6*(6-2b-3c)+2b-3c=23
and 5*(6-2b-3c)+4b-3c=-12
14b-15c=59
14b-18c=18/*(-1)
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3b=41
We know that the trigonometric identity that uses the adjacent side and the hypotenuse is cosine. We can set this up as:
We need to solve for x, so let's isolate it:
So,
x = 10.2 units
Its technically like 7/8 x 60 because 60 mins is an hour
I believe the answer is 2(15t).