I'm assuming the limit is supposed to be
Multiply the numerator by its conjugate, and do the same with the denominator:
so that in the limit, we have
Factorize the first term in the denominator as
The 
terms cancel, leaving you with
and the limand is continuous at 
, so we can substitute it to find the limit has a value of -1/18.
the one where they are diagonal from one another
<span>2r/5+7r/15=
LCM=15
(15\5=3*2r=6r)
15\15=1*7r=7r
answer=6r+7r\15
answer=13r\15</span>
How do you need help? with what? haha
Answer:
-8
Step-by-step explanation:
