3 years ago

Does distance from modem affect internet speed

1 answer:

5 0

It shouldn't, but to be honest, it kind of does.
The further you are away from the modem,
the less connectivity you have.
Because you can't connect really well, your internet slows down.

So... yes?

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The magnetic field produced by the solenoid in a magnetic resonance imaging (MRI) system designed for measurements on whole huma

Vesna [10]

Answer:

Number of turns per unit length will be $n=2.786\times 10^4turns/m$

Explanation:

We have given that strength of the magnetic field produced by the solenoid B = 7 T

Current in the solenoid i = 200 A

Let the number of turns per unit length is n

Magnetic field due to solenoid is given as $B=\mu ni$ here $\mu$ is permeability of free space n is number of turns per unit length and i is current

So $7=4\pi \times 10^{-7}\times n\times 200$

$n=2.786\times 10^4turns/m$

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2 years ago

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Which could be an example of a balanced force?

Rus_ich [418]

Answer:

An asteroid moving at a constant speed through space.

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How is air temperature related to high and low pressure air

vitfil [10]

Answer: So, I looked at it to see what was the correct one, and the correct answer is Cool air near surface forms high-pressure areas, warm air forms low pressure areas. I hope this helps :D :)

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2 years ago

the age of Egyptian pyramid about NTT power 11 years the mankind exist for 29 years how many seconds will be men have exist if a

Zepler [3.9K]

It makes no sense how you typed this problem out.

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2 years ago

A car has a kinetic energy of 1.9 × 10^3 joules. If the velocity of the car is decreased by half, what is its kinetic energy?

VLD [36.1K]

The initial kinetic energy of the car is
$E_1 = \frac{1}{2}mv_1^2 = 1.9 \cdot 10^3 J$

Then, the velocity of the car is decreased by half: $v_2 = \frac{v_1}{2}$
so, the new kinetic energy is
$E_2 = \frac{1}{2}mv_2 ^2 = \frac{1}{2} m ( \frac{v_1}{2} )^2= \frac{1}{2}m \frac{v_1^2}{4}= \frac{E_1}{4}$
So, the new kinetic energy is 1/4 of the initial kinetic energy of the car. Numerically:
$E_2 = \frac{1.9 \cdot 10^3 J}{4}=475 J$

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3 years ago