Answer:
<em>The initial speed of the sprinter was 2.2 m/s</em>
Explanation:
<u>Constant Acceleration Motion</u>
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
The following relation applies:
Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.
The sprinter speeds up from an unknown initial speed to vf=3 m/s in t=2 seconds with an acceleration of .
To find the initial speed, we solve the equation for vo:
Substituting the values:
The initial speed of the sprinter was 2.2 m/s
<em> In a refracting telescope </em><u><em>convex lens</em></u><em> forms the image.
</em>
<u>Answer:</u> <em>c. Convex mirror</em>
<u>Explanation:</u>
Telescope is an instrument used for magnification of distant objects. The convex lenses objective and eyepiece are the two parts of a refracting telescope.
Objective has a greater focal length when compared with the eyepiece. Image of a distant object is formed at the second focal point of the objective. This image is magnified by the eyepiece.
The objective and eyepiece lenses can only produce an inverted image since they both are convex lenses. The function of producing a final erect image is performed by a pair of inverting lenses.
Answer:
Q at the center of the distribution.
Explanation:
- The Gauss's law is the law that relates to the distribution of electrical charges to the resulting electrical field. It states that a flux of electricity outside the arabatory closed surface is proportional to the electricitical harg enclosed by the surface.
I think it would increase because the lynx is a predator of the snowhare
Answer 1) : 62.5 km/hour is the average velocity of the train.
2) The final velocity of the car at the end of 75 m is 14.69 m/s
Explanation:
1) Displacement of the train = 100 km + 150 km = 250 km
Total time train took =1 hour 15 min+ 45 min + 2 hours = 240 min = 4 hours
Average velocity=
62.5 km/hour is the average velocity of the train.
2) The acceleration of the car, a= 1.2
Distance covered by the car,s = 75 m
Initial velocity of the car , = 6 m/s
Final velocity of thre car ,=?
Using third equation of motion:
The final velocity of the car at the end of 75 m is 14.69 m/s