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2 years ago

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Which best describes the relationship between the line that passes through the points (1, –6) and (3, –2) and the line that pass

es through the points (4, 8) and (6, 12)

1 answer:

Setler [38]2 years ago

8 0

Both lines are parallel, since they have the same slope of 2.

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butalik [34]

8 goes into 153 19 times.

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2 years ago

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2/3y = 14/39<br> Please help me answer this.

Sati [7]

Answer: y =13 because y represents how the number of how many times you multiply 2/3 to get to 14/39 so you divide 39 by 3 and get 13. now if you times 2 by 13, you don't get fourteen so I'm confused on that part and I might be wrong so I'm sorry if I'm wrong

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3 years ago

M-80=150,doing homework

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M=230
m-80=150
add 80 to each sides

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2 years ago

In a two-digit number, the units digit is twice the tens digit. If the number is doubled, it will be 9 more than the number reve

taurus [48]

10(2x)+x
21x is the original number

12x is the reversed number
24x is the reversed then doubled number

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24x=21x+9
3x=9
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2 years ago

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An article presents a study of the failure pressures of roof panels. A sample of 15 panels constructed with 8-inch nail spacing

wariber [46]

Answer:

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject $H_0\ at\ 5%$ level of significance

Step-by-step explanation:

From the question we are told that:

Sample size 1 $n_1=15$

Spacing 1 $s_1=8$

Mean 1 $\=x_1=8.48$

Standard deviation 1 $\sigma_1=0.96 kPa$

Sample size 2 $n_2=16$

Spacing 2 $s_2=6$

Mean 1 $\=x_1=9.93$

Standard deviation 1 $\sigma_1=1.02 kPa$

Generally the hypothesis is mathematically given as

Null $H_0:\mu_1-\mu_2$

Alternative $H_a:\mu_1\mu_2$

Generally the equation for pooled estimate is mathematically given by

$S=\sqrt{\frac{(n_1-1)\sigma_1^2+(n_2-1)\sigma_2^2}{n_1+n_2-2} }$

Therefore

$S=\sqrt{\frac{(15-1)0.96^2+(16-1)1.02^2}{15+15-2} }$

$S=0.9905$

Generally the equation for test statistics is mathematically given by

$t=\frac{\=x_1+\=x_2}{S\sqrt{\frac{1}{n _1}+\frac{1}{n_2}}}$

$t=\frac{\=8.48-9.93}{0.9905\sqrt{\frac{1}{15}+\frac{1}{15}}}$

$t=-4.00091$

Therefore From table

$P value=P(t_{15+15-2}=4.00091)$

$P value=0.00041918$

$P$

Therefore

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject $H_0\ at\ 5%$ level of significance

3 0

2 years ago