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2 years ago

id="TexFormula1" title="\frac{x^{\frac{5}{6} } }{x^{\frac{1}{6} } }" alt="\frac{x^{\frac{5}{6} } }{x^{\frac{1}{6} } }" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Kryger [21]2 years ago

4 0

Answer:

x^2/3

Step-by-step explanation:

(x^5/6)/(x^1/6)=x^(5/6-1/6)=x^4/6

simplify 4/6, you get 2/3.

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Find the h.c.f by prime factorization method 27, 30

Orlov [11]

Answer:

Find it yourself . you must try yourself. rate me plzs

7 0

2 years ago

A box contains 3 green marbles, 5 blue marbles, and 7 red marbles. Three marbles are selected at random from the box, one at a t

USPshnik [31]

Answer:

The probability is $P(K) = \frac{ 28 }{195}$

Step-by-step explanation:

From the question we are told that

The number of green marbles is $n_g = 3$

The number of red marbles is $n_b = 5$

The number of red marbles is $n_r = 7$

Generally the total number of marbles is mathematically represented as

$n_t = n_r + n_g + n_ b$

$n_t = 7 + 3 + 5$

$n_t = 5$

Generally total number of marbles that are not red is

$n_k = n_g + n_ b$

=> $n_k = 3 + 5$

=> $n_k = 8$

The probability of the first ball not being red is mathematically represented as

$P(r') = \frac{n_k}{n_t}$

=> $P(r') = \frac{ 8}{15}$

The probability of the second ball not being red is mathematically represented as

$P(r'') = \frac{n_k - 1}{n_t -1}$

=> $P(r'') = \frac{ 8 -1 }{15-1}$ (the subtraction is because the marbles where selected without replacement )

=> $P(r'') = \frac{ 7 }{14}$

The probability that the first two balls is not red is mathematically represented as

$P(R) = P(r') * P(r'')$

=> $P(R) = \frac{ 8}{15} * \frac{ 7 }{14}$

=> $P(R) = \frac{ 8 }{30}$

The probability of the third ball being red is mathematically represented as

$P(r) = \frac{n_r}{ n_t -2}$ (the subtraction is because the marbles where selected without replacement )

$P(r) = \frac{7}{ 15 -2}$

=> $P(r) = \frac{7}{ 13}$

Generally the probability of the first two marble not being red and the third marble being red is mathematically represented as

$P(K) = P(R) * P(r)$

$P(K) = \frac{ 8 }{30} * \frac{7}{ 13}$

=> $P(K) = \frac{ 28 }{195}$

6 0

2 years ago

Consider the region bounded by 4y=x^2 and 2y=x.

gayaneshka [121]

Answer:

a) ⅓ units²

b) 4/15 pi units³

c) 2/3 pi units³

Step-by-step explanation:

4y = x²

2y = x

4y = (2y)²

4y = 4y²

4y² - 4y = 0

y(y-1) = 0

y = 0, 1

x = 0, 2

Area

Integrate: x²/4 - x/2

From 0 to 2

(x³/12 - x²/4)

(8/12 - 4/4) - 0

= -⅓

Area = ⅓

Volume:

Squares and then integrate

Integrate: [x²/4]² - [x/2]²

Integrate: x⁴/16 - x²/4

x⁵/80 - x³/12

Limits 0 to 2

(2⁵/80 - 2³/12) - 0

-4/15

Volume = 4/15 pi

About the x-axis

x² = 4y

x² = 4y²

Integrate the difference

Integrate: 4y² - 4y

4y³/3 - 2y²

Limits 0 to 1

(4/3 - 2) - 0

-2/3

Volume = ⅔ pi

7 0

2 years ago

Verify x + 1⁄2 is a factor of P(x)= x2 + x -2

kumpel [21]

Answer:

Put p(x)=0.

Step-by-step explanation:

2x-1=0 will give x=1/2. This means, If x=1/2 is given to the polynomial p(x), it will give a zero. P(1/2)=0.

8 0

2 years ago

Which expression is equivalent to 8x-2x+x+x a. 4x b. 8x c. 6x-2x d. 10x-2y

Deffense [45]

B - 8x

To find this, combine like terms.

8x - 2x is 6x, then add the two x's on the side to bring it back to 8x.

Hope this helps!

4 0

2 years ago

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