All categories

2 years ago

What is the sixth prime number

2 answers:

5 0

A prime number is a number that is divisible by itself and 1 only. Note that 1 itself is not a prime number.

So in our natural counting of numbers:

The 1st prime number is 2.

2nd is 3.

3rd is 5.

4th is 7.

5th is 11.

6th is 13.

So the 6th prime number is 13.

ElenaW [278]2 years ago

5 0

Sixth prime number is 13

You might be interested in

Four friends shared 1/2 of one carton of orange juice and 1/4 of another carton of apple juice. What fraction of each carton of

Natalka [10]

Answer:

$\dfrac{1}{16}$

$\dfrac{1}{32}$

$\dfrac{3}{32}$

Step-by-step explanation:

So in the first carton of orange juice 4 friends shared the juice.

This can be shown as:

$\dfrac{(\dfrac{1}{2})}{4}$

$\dfrac{(\dfrac{1}{2})}{4}=\dfrac{1}{16}$

The 4 friends got 1/16 of the carton each in the first carton of OJ.

Next for the second carton, it can be shown as:

$\dfrac{(\dfrac{1}{4})}{4}$

$\dfrac{(\dfrac{1}{2})}{4}=\dfrac{1}{32}$

The 4 friends got 1/32 of the carton each in the first carton of OJ.

Now to see how much they got in total each, we simply add 1/16 to 1/32

$Total OJ each = \dfrac{1}{16}+\dfrac{1}{32}$

$Total OJ each = \dfrac{3}{32}$

Each friend got a total of $\dfrac{3}{32}$ each from both cartons of OJ.

3 0

2 years ago

How to factor 15m^2-12m^3

tester [92]

Step 1. Find the Greatest Common Factor (GCF)
GCF = 3m^2
Step 2. Factor out the GCF (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
3m^2(15m^2/3m^2 + -12m^3/3m^2)
Step 3. Simplify each term in parentheses
3m^2(5 - 4m)

8 0

2 years ago

Read 2 more answers

The mean weight 20 students in a room is 65 kg one student one student who weight is 88kg went into the room what is the new mea

umka2103 [35]

The new mean is 66.09

Explanation:

Mean weight of 20 students = 65kg

One student with 88kg entered the room.

New mean = ?

$\frac{x_1+x_2+....+x_2_0}{20} = 65$

$\frac{x_1+x_2+....+x_2_0 + 88}{21} = ?$

The above equation can further be written as:

$x_1 + x_2 +....+x_2_0 = 65 X 20\\\\x_1 + x_2 +....+x_2_0 = 1300$

New mean = $\frac{1300 + 88}{21}$

= 66.09

Therefore, the new mean is 66.09

6 0

2 years ago

X and Y are continuous values, both measured to 2 significant figures. X=230 and Y=400. work out the greatest possible value of

kirill115 [55]

"Two significant figures" means that a digit after the second one could actually be anything ... it wasn't measured. 'X' could be anything from 230 to 239. 'Y' could be anything from 400 to 409. The greatest possible value of that fraction is. (239)/(409 squared) .

8 0

2 years ago

Order these numbers from least to greatest. 5 10/11 117/20 5.84 5.822

Sliva [168]

Least to greatest: 5 10/11 , 5.822 , 5.84, 117/20.

8 0

2 years ago