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"Tundra and desert" are the two biomes among the choices given in the question that <span>have the least precipitation. The correct option among all the options that are given in the question is the third option.
"Exposure to solar flares" is the one among the following choices given in the question that would not </span><span>be a factor that helps determine the characteristics of a land biome. The correct option among all the options given in the question is the first option.</span>
Answer and Explanation:
In rest, attraction strengths between myosin and actin filaments are inhibited by the tropomyosin. When the muscle fiber membrane depolarizes, the action potential caused by this depolarization enters the t-tubules depolarizing the inner portion of the muscle fiber. This activates calcium channels in the T tubules membrane and releases calcium into the sarcolemma. At this point, tropomyosin is obstructing binding sites for myosin on the thin filament. When calcium binds to the troponin C, the troponin T alters the tropomyosin by moving it and then unblocks the binding sites. Myosin heads bind to the uncovered actin-binding sites forming cross-bridges, and while doing it ATP is transformed into ADP and inorganic phosphate which is released. Myofilaments slide impulsed by chemical energy collected in myosin heads, producing a power stroke. The power stroke initiates when the myosin cross-bridge binds to actin. As they slide, ADP molecules are released. A new ATP links to myosin heads and breaks the bindings to the actin filament. Then ATP splits into ADP and phosphate, and the energy produced is accumulated in the myosin heads, which starts a new binding cycle to actin. Z-bands are then pulled toward each other, thus shortening the sarcomere and the I-band, and producing muscle fiber contraction.
Answer:
<h2>e) 3/4
</h2>
Explanation:
As given;
Black (B) is dominant over red (b), so B is dominant over b.
Solid (S) is dominant over spotted color(s), so S is dominant over s.
Offspring of BBss and bbss individuals are:
Gametes of parent BBss are Bs, Bs and gamete of bbss are bs, bs
offspring are : all Bbss
Cross between these offspring is; Bbss×Bbss
Gametes of parent Bbss are: Bs and bs as given that the genes are linked.
Bs, bs × Bb, bs
Offspring are = BBss, Bbss, Bbss, bbss
Black spotted (B_ss) = 3/4