Answer:
Anhydrous copper (II) sulphate is white because it has no water in it. When drops of water are added, copper (II) sulphate turns blue. This colour change can be used to detect the presence of water (or water vapour).
Answer:
NaOH(aq)
Explanation:
NaOH(aq) is known to precipitate Mn^2+ ions according to the following reaction; Mn^2+(aq)+2OH^−(aq)↽−−⇀Mn(OH)2(s)
Hence, manganese(II) oxide reacts more readily with NaOH(aq) under ordinary conditions precipitating the metal hydroxide solid. This is one of the characteristic reactions of Mn^2+.
Answer:
265 mL is the new volume for the gas
Explanation:
We decompose the Ideal Gases Law in order to find the answer of this question: P . V = n . R . T
We can propose the formula for the 2 situations, where n remains constant.
R refers to 0.082 L.atm/mol.K which is physic constant.
We convert the temperature to Absolute value:
67.5°C + 273 = 340.5 K
80°C + 273 = 353 K
We convert the volume to L → 242.2 mL . 1 L/1000 mL = 0.2422 L
We convert the pressure values to atm:
882 Torr . 1 atm/ 760 Torr = 1.16 atm
840 Torr . 1atm / 760 Torr = 1.10 atm
P₁. V₁ / T₁ = P₂ . V₂ / T₂ → Let's replace data:
1.16 atm . 0.2422L / 340.5K = 1.10 atm . V₂ / 353 K
(1.16 atm . 0.2422L / 340.5K) . 353K = 1.10 atm . V₂
V₂ = 0.291 L.atm / 1.10 atm → 0.2647 L ≅ 265 mL
<span>Phospholipids would have to form a phospholipid bilayer in order to achieve water on the outside and water inside. This is because the nonpolar tails of the phospholipids are facing each other in a water environment because they cannot interact with the water, only their own tails, while the phosphate heads of the molecule face the periphery of the tails and interact with water. Micelles are the simplest examples of these.</span>
<em>K</em> = 2.4 × 10^(-72)
<em>Step 1</em>. Determine the <em>value of n
</em>
Zn^(2+) + 2e^(-) → Zn
2Cl^(-) → Cl_2 + 2e^(-)
Zn^(2+) + 2Cl^(-) → Zn + Cl_2
∴ <em>n</em> = 2
<em>Step 2</em>. Calculate <em>K</em>
log<em>K</em> = <em>nE</em>°/0.0592 V = [2 × (-2.12 V)]/0.0592 V = -71.62
<em>K</em> = 10^(-71.62) = 2.4 × 10^(-72)
