Answer:
Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proof is below.
Step-by-step explanation:
Given:
In Δ PQT
PQ = 30 ft
QT = 28 ft
TP = 20 ft
In Δ QRS
QR = 15 ft
RS = 14 ft
SQ = 10 ft
To Prove:
Δ PQT ~ Δ QRS
Proof:
First we consider the ratio of the sides
..............( 1 )
..............( 2 )
..............( 3 )
So By equation ( 1 ), ( 2 ) and ( 3 ) we get
Now in Δ PQT and Δ QRS we have
Which are corresponding sides of a similar triangle in proportion.
∴ Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proved
Answer:
10x - 3
Step-by-step explanation:
First, distribute 2 to all terms within the second parenthesis:
2(3x + 1) = (2 * 3x) + (2 * 1) = 6x + 2
4x - 5 + 6x + 2
Combine like terms (terms with the same amount of variables).
4x + 6x + 2 - 5
(4x + 6x) + (2 - 5)
10x + (-3)
10x - 3
10x - 3 is your answer.
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Well in my calculations I got: well if you he increases the speed by 2.6 per hour soo 4+2.6=6.6
Answer:
14
Step-by-step explanation:
3 times 14 equals 42, and 42 divided by 2 is 21. 21 divided by 3 is 7. :)
a) the independent variable is the number of training miles.
b) the dependent variable is the cost to mail the package
c) the dependent variable is P
