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8_murik_8 [283]

2 years ago

10

There are 32 female performers in a dance recital. The ratio of men to women is 3:8. How many men are in the dance recital??????

PLEASE HELP WILL MARK BRAINLIEST

1 answer:

nydimaria [60]2 years ago

6 0

Answer:

12

Step-by-step explanation:

3/8=x/32

8x=96/32

x=12

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What is the area of a trapezoid with 5m and bases 8 m and 1 m ?

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Let f(x)= 100 / −10+ e^ −0.1x . What is f(−6) ?

bija089 [108]

The value of f(-6) is -12.2

Explanation:

Given that the function $f(x)=\frac{100}{-10+e^{-0.1\left(x\right)}}$

We need to determine the value of f(-6)

The value of f(-6) can be determined by substituting the value for $x=-6$ in the function and simplify the function.

Hence, let us substitute $x=-6$ in the function, we get,

$f(-6)=\frac{100}{-10+e^{-0.1\left(-6\right)}}$

Let us apply the rule $-\left(-a\right)=a$ , we get,

$f(-6)=\frac{100}{-10+e^{0.1\left(6\right)}}$

Multiplying the numbers, we get,

$f(-6)=\frac{100}{-10+e^{0.6}}$

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$f(-6)=\frac{100}{-10+1.822}$

Subtracting the denominator, we have,

$f(-6)=\frac{100}{-8.178}$

Dividing, we have,

$f(-6)=-12.228$

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2 years ago

Solve 4+2h < -3 please help me and please show work

anastassius [24]

4 + 2h < -3
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2 years ago

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$

$xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}$

$xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}$

$xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)$

$\implies \boxed{xyz = x + y + z + 2}$

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2 years ago