Answer:
Δλ = 3*10⁻³ m.
Explanation:
- At any wave, there exists a fixed relationship between the speed of the wave, the wavelength, and the frequency, as follows:
where v is the speed, λ is the wavelength and f is the frequency.
- Rearranging terms, we can get λ from the other two parameters, as follows:
- Since v is constant for sound at 343 m/s, we can find the different wavelengths at different frequencies, as follows:
- The difference between both wavelengths, is just the difference between (3) and (4):
⇒ Δλ = 3*10⁻³ m.
Answer:
a)Yes will deform plastically
b) Will NOT experience necking
Explanation:
Given:
- Applied Force F = 850 lb
- Diameter of wire D = 0.15 in
- Yield Strength Y=45,000 psi
- Ultimate Tensile strength U = 55,000 psi
Find:
a) Whether there will be plastic deformation
b) Whether there will be necking.
Solution:
Assuming a constant Force F, the stress in the wire will be:
stress = F / Area
Area = pi*D^2 / 4
Area = pi*0.15^2 / 4 = 0.0176715 in^2
stress = 850 / 0.0176715
stress = 48,100.16 psi
Yield Strength < Applied stress > Ultimate Tensile strength
45,000 < 48,100 < 55,000
Hence, stress applied is greater than Yield strength beyond which the wire will deform plasticly but insufficient enough to reach UTS responsible for the necking to initiate. Hence, wire deforms plastically but does not experience necking.
Microscopes with life science and physics
Answer:
Hence the answer is E inside .
Explanation:
E inside
so if r1 will be the same then
E proportional to 1/R3
so if R become 2R
E becomes 1/8 of the initial electric field.