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2 years ago

Segments cf, eb, and ad are medians of triangle ace. cf = 3.6 m. what is the length of segment cg?

Mathematics

1 answer:

Vaselesa [24]2 years ago

6 0

Assuming g is the centroid, it is 2/3 of the length of cf from point c.
cg = (2/3)cf = (2/3)3.6 m
cg = 2.4 m

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Find the value of x.<br> (5x + 5)

Ivahew [28]

5( x + 1)

I hope this helps:)

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2 years ago

Bob makes 4% commission on his sales as a real estate agent. If Bob sells a house for $249,000, how much money does he get to ke

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He gets to keep $9,960 of the sale

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2 years ago

Can somebody help me, please?

Sveta_85 [38]

Answer:

a. $x=10 \textdegree$

$m\angle L=39\textdegree\\\\m\angle M=51\textdegree\\\\m\angle K=90\textdegree$

Step-by-step explanation:

a. We know that angles in a triangle add up to 180°.

-The right angle triangle in the right triangle has a measure of 90°.

We can therefore equate our angles to 180° and solve for x;

$180=\perp\angle+(2x+19)+(3x+21)\\\\180=90+(2x+19)+(3x+21)\\\\90=5x+40\\\\5x=50\\\\x=10\textdegree$

Hence, the angle measure is x=10°

b. Having calculated the value of x from a above as x=10°, we can substitute to find the measures of the two acute angles:

$m\angle L=(2x+19)\textdegree\\\\=(2\times 10+19)\textdegree\\\\=39\textdegree\\\\m\angle M=(3x+21)\textdegree\\\\=(3\times 10+21)\textdegree\\\\=51\textdegree$

Since, the m∠K is a right angle, it measures 90°

8 0

2 years ago

Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i

shepuryov [24]

Answer:D) 1 hr

Step-by-step explanation:

Given

Pump A and B can fill tank in $\frac{6}{5} hr$

Pump A and C can fill tank in $\frac{3}{2} hr$

Pump B and C can fill tank in $2 hr$

Let A be the total hr taken A therefore rate of $A=\frac{1}{A} /hr$

Let B be the total hr taken B therefore rate of $B=\frac{1}{B} /hr$

Let C be the total hr taken C therefore rate of $C=\frac{1}{C} /hr$

$\frac{1}{A}+\frac{1}{B}=\frac{5}{6}$ -----1

$\frac{1}{B}+\frac{1}{C}=\frac{1}{2}$ -----2

$\frac{1}{A}+\frac{1}{C}=\frac{2}{3}$ -----3

Adding 1,2 & 3

$2(\frac{1}{A}+\frac{1}{B}+\frac{1}{C})=\frac{5}{6}+\frac{1}{2}+\frac{2}{3}$

$\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{2}{2}$

$\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1$

thus time taken by A,B and C combined is 1 hr

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2 years ago

A weather forecaster says the temperature will be about-5C “give or take” 10 degrees. What is the greatest possible temperature?

IRINA_888 [86]

The greatest possible temperature is $5^{\circ} \mathrm{C}$ and least possible temperature is $-15^{\circ} \mathrm{C}$

<u>Solution:</u>

Given that according to weather forecaster the temperature will be about -5 degree celsius given or take 10 degree”

Need to determine greatest possible temperature and least possible temperature.

Give and take in given statement means a temperature can go up by 10 degrees and can go down by 10 degrees

So greatest possible temperature will be $-5^{\circ} \mathrm{C}+10^{\circ} \mathrm{C}=5^{\circ} \mathrm{C}$

Least possible temperature will be $-5^{\circ} \mathrm{C}-10^{\circ} \mathrm{C}=-15^{\circ} \mathrm{C}$

Hence according to weather forecaster, greatest possible temperature = $5^{\circ} \mathrm{C}$ and least possible temperature = $-15^{\circ} \mathrm{C}$

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2 years ago