A. solve for 1 variable
let's solve for x in 2nd equation
add 2y to both sides
x=2y+4
sub 2y+4 for x in other equation
3(2y+4)+y=5
6y+12+y=5
7y+12=5
minu12 both sides
7y=-7
divide 7
y=-1
sub back
x=2y+4
x=2(-1)+4
x=-2+4
x=2
(2,-1)
B. eliminate
eliminate y's
multiply first equation by 2 and add to first
6x+2y=10
<u>x-2y=4 +</u>
7x+0y=14
7x=14
divide by 7
x=2
sub back
x-2y=4
2-2y=4
minus 2
-2y=2
divide -2
y=-1
(2,-1)
(2,-1) is answer
Answer:
The equation of the graph in slope-intercept form is y = 3x + 7. 2. slope-intercept form is y = x + 2.
The first thing we must do for this case is to equal both functions and clear the value of x. Thus, we obtain the values that satisfy both equations.
However, there is another solution route. We have a table with the values.
The solution for f (x) = g (x) will be all x satisfying both equations simultaneously.
f (0) = g (0) = 1
f (1) = g (1) = 1/2
answer
x = 0
x = 1
Note:
F (0) in the table is incorrect if the function is
f (x) = 0.5x
F (0) in the table is correct if the function is
f (x) = 0.5 ^ x
Answer:
The distance between the hands is √(3)cm ≈ 1.73cm.
Step-by-step explanation:
In a standard clock, the angle between every number is 30°, therefore the angle between 12 and 2 will be 30° x 2 = 60°.
Looking at the diagram, to find c we can make use of our cosine formula
c² = a² + b² –2abCos(C°)
a = 2, b = 1 and C° = 60°
Therefore we have:
c² = 2² + 1² –2 x 2 x 1 x cos(60°) =
c² = 4 + 1 – 4 x 0.5 =
c² = 5 – 2 =
c² = 3
c = √(3) ≈ 1.73
Therefore, the distance between the hands is √(3)cm ≈ 1.73cm.
Answer:
BC= 20 units
Step-by-step explanation:
Since ∆ ABC is an equilateral triangle, all the sides are equal in length.
AC= BC
=>-y+23= 6y+2
=>-y-6y= 2-23
=>-7y= -21
=>y= 21/7
=>y= 3
BC = 6y+2 = 6(3)+2 = 18+2 = 20 units