The average expiratory reserve volume or ERV is 810.
<h3>What is expiratory reserve volume?</h3>
- Expiratory reserve volume or ERV is the amount of air that is exhaled forcibly.
- This can be measured using a spirometer and is used to detect restrictive lung diseases.
- It is the maximum amount of air that can be exhaled after normal tidal volume is exhaled.
- Respiratory volume is the volume of air which is either inhaled, exhaled or stored in your lungs.
- The doctors estimate the reserve volume with the help of spirometer to determine some lung diseases.
- Once diagnosed with a lung disease, spirometry is used to monitor it.
- Here, 3 readings of ERV are taken, calculate the sum of the these and divide by 3 to calculate the average ERV.
- ERV= (800+ 850+ 780)/ 3= 810
Learn about tidal volume here:
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They are similar to those of primary succession, primary succession occurs in an area without any initial. Succession always begins on a barren surface, whereas secondary succession be gains in environments that already possess soil. I hope this helps.
The palisade mesophyll has long cylinder shaped cells, lots of chloroplasts, cells closely packed together and large size of cells.
Answer:
See the explanation
Explanation:
Answer 1.
As given that in F1 all are short and white then it can be said according to Mendel's law that short and white are dominant over tall and purple.
Let S for short s for tall and W for white and w for purple allele.
So the genotype of short purple will be Ssww or SSww. So In first case Ssww self crossed then resultant offsprings will be,
................ Sw .................... sw
Sw ........ SSww ............. Ssww
sw ........ Ssww .............. ssww (tall and purple)
So from this 1/4 will be tall and purple while 3/4 will be short and purple.
In second case SSww only short purple progeny will appear.
Answer 2.
2. a) The female progeny will not show any trait because there are two X chromosome in females , so female offspring can be carrier but not show any trait in case of X- linked trait.
2. b) Half of male offsprings show trait because X is inherited from mother. So the chance of having X-linked recessive allele is 1/2.
2. c) The chance of having X linked affect allele in daughter is 1/2. So the chance of inheriting that X to son will be 1/2 so in total there is chance of 1/4 that son will be affected.
2. d) the chance of first child show this trait will be 1/4 in case of male offspring while 0 in case of female offspring.
Hope this helps!