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2 years ago

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Anyone good at composite functions??

1 answer:

sammy [17]2 years ago

6 0

$\bf \begin{cases} ~\hfill f(x) = &-3x+4\\ ~\hfill g(x) = &x^2\\ (g \circ f)(0)=&g(~~f(0)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(0) = -3(0)+4\implies \boxed{f(0) = 4} \\\\\\ g(~~f(0)~~)\implies g\left( \boxed{4} \right) = (4)^2\implies \stackrel{(g \circ f)(0)}{g(4)} = 16$

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A large scale weigh 3000 pound 5 ounces, which of the following scale weigh in ounces

Iteru [2.4K]

Answer:

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Step-by-step explanation:

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7 0

2 years ago

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polet [3.4K]

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4 0

2 years ago

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ryzh [129]

Answer:

Step-by-step explanation:

Hello,

$\dfrac{p}{q}*\dfrac{q}{p}=1=(2x+2)(2-x)\\\\ 4x-2x^2+4-2x=1\\\\ -2x^2+2x+4-1=0\\\\ -2x^2+2x+3=0\\\\$

There are two solutions

$\Delta=b^2-4ac=2^2+4*2*3=4+24=28=7*4\\x_1=\dfrac{-2+\sqrt{7*4}}{-4}=\dfrac{-2+2\sqrt{7}}{-4}=\dfrac{1-\sqrt{7}}{2}\\x_2=\dfrac{1+\sqrt{7}}{2}\\$

Hope this helps

5 0

2 years ago

A spaceship launched into the air has a height (feet) at any given time (seconds) as h=-t^2+10t until it hits the ground. At wha

Bas_tet [7]

Answer:

The spaceship is at a height 9 feet above the ground at 1 second and 9 second after lunched.

Step-by-step explanation:

Given that a spaceship launched into the air has a height at any time as

$h=-t^2+10t$

where h is height in feet and t is time in second.

To find the time when the height of the spaceship is 9, we need to put h=9 in the given equation.

$\therefore 9=-t^2+10t$

$\Rightarrow t^2-10t+9=0$

$\Rightarrow t^2-9t-t+9=0$

$\Rightarrow t(t-9)-1(t-9)=0$

$\Rightarrow (t-9)(t-1)=0$

$\Rightarrow t=1,9$

The spaceship is at a height 9 feet above the ground at 1 second and 9 second after lunched.

4 0

3 years ago

The denominator of a fraction is 5 more than twice the numerator. If both numerator and denominator are decreased by 7, the simp

Ugo [173]

Answer:

numerator is 10

denominator is 25

Step-by-step explanation:

let x be the numerator

let y be the denominator

write 2 equations:

y = 5 + 2x

$\frac{x-7}{y-7}$ = $\frac{1}{6}$

y is already isolated in the first equation, substitute into the second equation:

$\frac{x-7}{5+2x-7}$ = $\frac{1}{6}$

simplify:

$\frac{x-7}{2x-2}$ = $\frac{1}{6}$

cross multiply:

2x - 2 = 6(x - 7)

simplify:

2x - 2 = 6x - 42

subtract 2x:

-2 = 4x - 42

add 42:

4x = 40

divide by 4:

x = 10

plug in 10 for x in the first equation:

y = 5 + 2(10)

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y = 25

numerator is 10

denominator is 25

6 0

2 years ago