Which of these is an example of a literal equation? A. 3x – 4y B. 12 = 9 + 3x C. 6 + 30 = 62 D. ax – by = k

Mathematics

2 answers:

nika2105 [10]2 years ago

8 0

I think the answer is D.

yan [13]2 years ago

3 0

Is the answer. I did it with my teacher

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I don't know I need help please

Leya [2.2K]

It's the same angle. The equation, then, is 5y+1=51. Subtract one from both sides, so now you've got 5y=50. Divide each side by 5 and you've got y=10.

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2 years ago

ASAP some answer this ASAP

tatyana61 [14]

This answe would have to be (-3,7)

5 0

9 months ago

Read 2 more answers

What is the solution of <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B2%7D%7B4%7D%20%3D%20%5Cfrac%7Bx%2B8%7D%7B3%7D" id="TexFo

Lina20 [59]

Answer:

x = -26

Step-by-step explanation:

Multiply both sides by the lowest common multiple of 4 and 3, which is 12.

3(x+2) = 4(x+8)

3x + 6 = 4x + 32 --- distribute the 4 and 3

6 = x + 32 --- subtract 3x from both sides

-26 = x --- subtract 32 from both sides

x = -26

6 0

2 years ago

Find the difference between points M(6,16) and Z(-1,14) to the nearest tenth.

svlad2 [7]

I'm not sure what you mean by difference, so I am guessing you meant to write "distance". If this is not the case, then feel free to report me. Anyway, to find the distance between two points you would use the distance formula.

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

Let's substitute our point coordinates into the formula. We'll substitute -1 and 6 for x_2 and x_1, and 14 and 16 for y_2 and y_1. After substituting, your formula will now look like: $d=\sqrt{(-1-6)^2+(14-16)^2}$ .