Answer:
So the right answer is none
Step-by-step explanation:
-6≤1+3x
3x≥-7
x≥-2,33
-2,33>-5>-6>-11
so none of those are bigger then -2,33 and x is bigger then -2,33
Answer:
The z-score of a male bird of this species with a weight of 29.37 grams is 1.7.
Step-by-step explanation:
We are given that the weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation of 1.1 grams.
<u><em>Let X = weights of adult male birds of a certain species</em></u>
So, X ~ Normal()
The z score probability distribution for normal distribution is given by;
Z = ~ N(0,1)
where, = population mean weight = 27.5 grams
= standard deviation = 1.1 grams
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
SO, the z-score of a male bird of this species with a weight of 29.37 grams is given by;
<u>Z score</u> = =
= <u>1.7</u>
All you have to do is plug and solve...
2(q+2) + 3q = -26
2q + 4 + 3q = -26
Subtract 4 from the left side and move it to the right...
2q + 4 + 3q = -26
- 4 - 04
_________________
2q + 3q = -30
Now add 3q and 2q together and you get 5q, next divide...
5q = -30
_______
5 5
Finally, you get q equal to negative 6 (-6)!
Answer:
a. Class width=4
b.
Class midpoints
46.5
50.5
54.5
58.5
62.5
66.5
70.5
c.
Class boundaries
44.5-48.5
48.5-52.5
52.5-56.5
57.5-60.5
60.5-64.5
64.5-68.5
68.5-72.5
Step-by-step explanation:
There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,
Class
Interval frequency
45-48 1
49-52 3
53-56 5
57-60 11
61-64 7
65-68 7
69-72 1
a)
Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.
Class width=49-45=4
b)
The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.
Class
Interval Midpoints
45-48
49-52
53-56
57-60
61-64
65-68
69-72
c)
Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.
Class
Interval Class boundary
45-48 44.5-48.5
49-52 48.5-52.5
53-56 52.5-56.5
57-60 56.5-60.5
61-64 60.5-64.5
65-68 64.5-68.5
69-72 68.5-72.5
The answer should be number two