To find where on the hill the canonball lands
So 0.15x = 2 + 0.12x - 0.002x^2
Taking the LHS expression to the right and rearranging we have -0.002x^2 + 0.12x -
0.15x + 2 = 0.
So we have -0.002x^2 - 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x^2 + 0.03x -2 = 0.
This is a quadratic eqn with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25. The second solution y = 0.15 * 25 = 3.75
The correct answer is 77 degrees
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√(-√2-(-√2))²+(√3-2√3)²= 3
Step-by-step explanation:
Since , internal sum of angle of triangle is 180°
So,
66 + x +49 + x+83 = 180
or, 198 + 2x = 180
or, 2x = 180 -198
or, 2x = -18
hence, x = - 9
Now angle A = x + 49
= (-9) + 49
= 40
<u>Hence </u><u>measure</u><u> </u><u>of </u><u>angle </u><u>A </u><u>is </u><u>4</u><u>0</u><u>°</u><u>.</u>