Answer:
f^1/4
Step-by-step explanation:
Answer:
37°
Step-by-step explanation:
we're going to use cosine rule In calculating for the value of angle A
note that cosine rule can be used when two sides are given with an included angle . from the diagram above, the two sides given are side AB and side AC and the included angle is A
Hence cosine rule
a^2 = AB^2+AC^2 - 2AB×AC Cos A
3.2^2= 2.1^2+4.6^2-2×2.1×4.6COSA
10.24 =4.41+21.16- 19.32 COSA
10.24 = 25.57-19.32COSA
10.24-25.57= -19.32COSA
-15.33= -19.32COSA
dividing bothsides by - 19.32
COSA= -15.33/19.32
COA= 0.79347826
A = COS^-1 (0.79347826)
A= 37.488
A= 37°
<h2>hope this helps!!</h2>
Answer:
Yolanda should have found the volume by multiplying 8 by 2/3.
Step-by-step explanation:
<u><em>Answer:</em></u>
SAS
<u><em>Explanation:</em></u>
<u>Before solving the problem, let's define each of the given theorems:</u>
<u>1- SSS (side-side-side):</u> This theorem is valid when the three sides of the first triangle are congruent to the corresponding three sides in the second triangle
<u>2- SAS (side-angle-side):</u> This theorem is valid when two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle
<u>3- ASA (angle-side-angle):</u> This theorem is valid when two angles and the included side between them in the first triangle are congruent to the corresponding two angles and the included side between them in the second triangle
<u>4- AAS (angle-angle-side):</u> This theorem is valid when two angles and a side that is not included between them in the first triangle are congruent to the corresponding two angles and a side that is not included between them in the second triangle
<u>Now, let's check the given triangles:</u>
We can note that the two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle
This means that the two triangles are congruent by <u>SAS</u> theorem
Hope this helps :)
