If
<em>f(x)</em> = <em>ax</em> ³ + <em>bx</em> ² - 5<em>x</em> + 9
then
<em>f '(x)</em> = 3<em>ax </em>² + 2<em>bx</em> - 5
Given that <em>f</em> (-1) = 12 and <em>f</em> '(-1) = 3, we get the system of equations
-<em>a</em> + <em>b</em> + 5 + 9 = 12
3<em>a</em> - 2<em>b</em> - 5 = 3
or
-<em>a</em> + <em>b</em> = -2
3<em>a</em> - 2<em>b</em> = 8
Multiply through the first equation by 2 and add it to the second one to eliminate <em>b</em> and solve for <em>a</em> :
2(-<em>a</em> + <em>b</em>) + (3<em>a</em> - 2<em>b</em>) = 2(-2) + 8
-2<em>a</em> + 2<em>b</em> + 3<em>a</em> - 2<em>b</em> = -4 + 8
<em>a</em> = 4
Substitute this into the first equation above to solve for <em>b</em> :
-4 + <em>b</em> = -2
<em>b</em> = 2
Option 3, definition of congruent segments is the answer I'm pretty sure
Answer:
1
Step-by-step explanation:
(9²/3⁴)³ = (81/81)³ = 1³ = 1
Answer:
e^x^3 = xy :
Step-by-step explanation:
=)
Answer:
x = 1.5
Step-by-step explanation:
Here, we want to solve for the value of x
By using the tangent from the same point theorem, we have it that;
lh^2 = lj * lk
1^2 = (0.5) * (0.5 + x)
1 = 0.5x + 0.25
1-0.25 = 0.5x
0.5x = 0.75
x = 0.75/0.5
x = 1.5