The word in the problem that indicates is a negative number is “descend”
Answer:
125
Step-by-step explanation:
f(1)= the first time (32,000)
n= 9
r= .5 (each term is being mulitplied by .5 to get the next one
We have
32,000*(.5)^(9-1)
32,000*(.5)^8
=125
Answer:
No.
Step-by-step explanation:
Any even number plus any odd number will always be odd.
Hope this helps Buddy!
Please mark me brainliest!
~Courtney
You should search it up on Photomath is easier
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
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If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
