Answer:
The wall is 10.5 foot far from the bottom of the ladder.
Step-by-step explanation:
Given:
Height of the ladder leaning against wall (Hypotenuse) = 20 foot.
Height from where the window is above from the ground (Leg1) = 17 feet.
To find the distance of the bottom of the ladder far from the wall (Leg2) = ?
Now, by using the pythagorean theorem:
by squaring both sides
10.535 foot rounded nearest tenth is 10.5 foot.
Therefore, the wall is 10.5 foot far from the bottom of the ladder.
Answer:
look at the picture .................
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
Find out more on equation at: brainly.com/question/2972832
#SPJ1
5+2h i think this is how it would be represented
