A. 5 invitations
b. 15 invitations
Comment if you need me to explain it.
Step-by-step answer:
We are looking at the coefficient of the 22nd term of (x+y)^25.
Following the sequence, first term is x^0y^25, second term is x^1y^24, third term is x^2y^23...and so on, 22nd term is x^21y^4.
The twenty-second term of (x+y)^25 is given by the binomial theorem as
( 25!/(21!4!) ) x^21*y^4
=25*24*23*22/4! x^21y^4
= 12650 x^21 y^4
The coefficient required is therefore 12650, for a binomial with unit valued coefficients.
For other binomials, substitute the values for x and y and expand accordingly.
Question would have been more clearly stated if the actual binomial was given, as commented above.
Answer:
<h3>3×(-4) = y - 5</h3><h3>= ) -12 = y -5 </h3><h3>=) -12 +5 =y </h3><h3>=) -7 = y</h3>
<h2>y =-7</h2>
You just have to do the opposite of what Corey did.
So (18 ÷3 +17) ×2 -25
The answer is 21
Hope I can help you, brainliest answer? :)
Answer:
you can do a diagram representing this product by drawing a box with six squares and then putting three lines for each box and divide 3÷3 and you will get 5
