Answer:
(x - 3)(x + 1)(x + 5)
Step-by-step explanation:
I'd use synthetic division instead. If we were to find the roots of the given polynomial, we could from them write the factors as well.
The divisor x + 5 corresponds to root x = -5. Setting up synthetic div.,
-5 ) 1 3 -13 -15
-5 10 +15
-----------------------------
1 -2 -3 0
Since the remainder is 0, we know that -5 is a root and (x + 5) is a factor. Moreover, we know that the coefficients of the quotient are 1, -2 and -3.
1x² - 2x - 3 can be factored: the factors are (x - 3) and (x + 1).
So the end result for this problem is (x - 3)(x + 1)(x + 5).
Answer:
Step-by-step explanation:
÷ 
= 
= 
= 1
Use KCF method,
Keep the first number.
Change the division to multiplication
Flip the second number
For ΔABD, it is given that side AB is congruent to side CB, that ∠ABD is congruent to ∠CBD. In order to invoke the SAS Postulate, the remaining side(s) fo the triangles must be shown to be congruent. Those sides are BD and BD.
The appropriate choice is ...
... b. BD ≅ BD
