The 15th term in the given A.P. sequence is a₁₅ = 33.
According to the statement
we have given that the A.P. Series with the a = 5 and the d is 2.
And we have to find the 15th term of the sequence.
So, for this purpose we know that the
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
And the formula is a
an = a + (n-1)d
After substitute the values in it the equation become
an = 5 + (15-1)2
a₁₅ = 5 + 28
Now the 15th term is a₁₅ = 33.
So, The 15th term in the given A.P. sequence is a₁₅ = 33.
Learn more about arithmetic progression here
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The domain is 2x and the range is -6
Answer: Felipe= 106
Teresa=98
Pablo=464
Step-by-step explanation:
Since Pablo has 4 times you do $106x4=464 and Teresa has 8 less so $106-8= $98
Answer:
1
Step-by-step explanation:
Any positive integer to power of 0 will ALWAYS be 1.