Given :
2.5 mole of Sulfuric acid .
To Find :
Mass of sodium hydroxide will completely neutralize 2.5 mol of sulfuric acid
Solution :
Let us assume volume of water be 1 L .
Now , we know , to neutralize 1 mole of sulfuric acid we need 2 moles of NaOH .
So , for 2.5 mole sulfuric acid required 5 mole of NaOH .
Moles of NaOH ,
Molecular mass of NaOH , M.M = 58.44 g/mol .
Mass of 5 moles of NaOH :
Hence , this is the required solution .
Mixing of pure orbitals having nearly equal energy to form equal number of completely new orbitals is said to be hybridization.
For the compound, the electronic configuration of the atoms, carbon and hydrogen are:
Carbon (atomic number=6): In ground state=
In excited state:
Hydrogen (atomic number=1):
All the bonds in the compound is single bond(-bond) that is they are formed by head on collision of the orbitals.
The structure of the compound is shown in the image.
The Carbon-Hydrogen bond is formed by overlapping of s-orbital of hydrogen to p-orbital of carbon.
In order to complete the octet the required number of electrons for carbon is 4 and for hydrogen is 1. So, the electron in of hydrogen will overlap to the 2p^{3}-orbital of carbon.
Thus, the hybridization of Hydrogen is -hybridization and the hybridization of Carbon is
-hybridization.
The hybridization of each atom is shown in the image.
