Answer:
The magnetic field inside the solenoid would decrease by a factor of 2.
Explanation:
The magnetic field, B, of a solenoid of length L, N windings, and radius b with a current, I, flowing through it is given as:
B = (N * r * I) / L
If the length of the solenoid is doubled, 2L,the magnetic field becomes:
B2 = (N * r * I) / 2L
B2 = ½ B
The magnetic field will decrease by a factor of 2.
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