Find the perpendicular line then find the intersection then find the point
perpendicular lines have slopes that are perpendicular
the slopes multiply bo -1
y=mx+b
m=slope
y=2x-3
2 is slope
2 times what=-1
what=-1/2
the equation is
y-3=-1/2(x-8) or
y=(-1/2)x+7
find intersection
at (4,5)
distance bwetweeen (8,3) and (4,5)
D=
D=
D=
D=
D=2√5
distance= 2√5
Answer:
Step-by-step explanation:
By triangle sum theorem,
Sum of all angles of a triangle is 180°.
m∠1 + m∠2 + m∠3 = 180°
(m∠1 + m∠3) + m∠2 = 180°
2(m∠1) + 70° = 180° {Given → m∠1 = m∠3]
2(m∠1) = 110°
m∠1 = 55°
Therefore, m∠1 = m∠3 = 55°
The answer is: " x < -3 " .
_____________________
Explanation:
_____________________
Given:
______________________
" 9(2x + 1) < 9x – 18 " ;
First , factor out a "9" in the expression on the right-hand side of the inequality:
9x – 18 = 9(x – 2) ;
and rewrite the inequality:
_____________________
9(2x + 1) < 9(x – 2) ;
Now, divide EACH SIDE of the inequality by "9" ;
[9(2x + 1)] / 9 < [9(x – 2)] / 9 ;
to get:
2x + 1 < x – 2 ;
Now, subtract "x" and add "2" to each side of the inequality:
2x + 1 – x + 2 < x – 2 – x + 2 ;
to get:
x + 3 < 0 ;
Subtract "3" from EACH SIDE ;
x + 3 – 3 < 0 – 3 ;
to get:
" x < -3 " .
____________________________________
Answer:
A and D
Step-by-step explanation:
Third degree polynomials refers to polynomials that has 3 as the greatest power of the variable.
A. 3 x y − 3 x y^2
Degree = 1 + 2 = 3
This option is correct
B 2y - xy^3 + 7
Degree = 1 + 3 = 4
This option is wrong
C. 3x^3y^2 -3x^2y + 10y^2 - 10y
Degree = 3 + 2 = 5
This option is wrong
D. 3x^2y+5xy
Degree = 2 + 1 = 3
This option is correct
E. 3y^3 + 3x^3 y^4
Degree = 3 + 4 = 7
This option is wrong
Answer: just graph these two equations
option a: y = 5x + 10
option b: y = 7.5x
and then tell at what number of event would having a card and not having a card is cheaper.
Step-by-step explanation:
the initial cost, $10, is your b value for the equation y = mx + b so yo would start here on the y axis. but for the second option you start at zero since you don't have a b value