Answer:
6 m/s
Explanation:
12m / 2s = 6 m/s
Hope that's the answer you seek.
The answer is 12.5 kg because 250N / 20m/s^2
I hope that helped
A. Using the third equation of motion:
v2 = u2 + 2as
from the question;
the jet was initially at rest
hence u = 0
a = 1.75m/s2
s = 1500m
v2 = 02 + 2(1.75)(1500)
v2 = 5250
v = √5250
v = 72.46m/s
hence it moves with a velocity of 72.46m/s.
b. s = ut + 1/2at2
1500 = 0(t) + 1/2(1.75)t2
1500 × 2 = 2× 1/2(1.75)t2
3000 = 1.75t2
1714.29 = t2
41.4 = t
hence the time taken for the plane to down the runway is 41.4s.
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Answer:
(a) Time t = 16.46 sec
(b) Time t =13.466 sec
(c) Deceleration =
Explanation:
(a) As the train starts from rest its initial velocity u = 0 m/sec
Acceleration
Final speed v = 80 km/hr
From first equation of motion v =u+at
So
(b) Now initial speed u = 22.22 m/sec
As finally train comes to rest so final speed v=0 m/sec
Deceleration
So
(c) We have given that initial velocity = 80 km/hr = 22.22 m/sec
Final velocity v = 0 m/sec
Time t = 8.30 sec
So acceleration is given by
As acceleration is negative so it is a deceleration
Answer:
The last one, nicotine from tobacco