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Ganezh
[65]
2 years ago
6
Find the product (2x^2+tv)(3x^2-3tv)
Mathematics
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1
answer:
vodka
[1.7K]
2 years ago
5
0
= 2x^2 * 3x^2 + - 2x^2 * 3tv + 3x^2tv - 3t^2v^2
= 6x^4 - 6x^2tv + 3x^2tv - 3t^2v^2
= 6x^4 - 3x^2tv - 3t^2v^2
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